Example # 1
S.H.M |
a) A to B
b) O to B
c) O to C
d) D to E
Answers:
Note that the period is the time taken to complete one revolution in this case the period is the time taken for the particle to travel from A to B and then to A again (24 seconds as stated in the question above).
a) A to B
A to B is half a period which would be = 12 second
If you want to work this question in a more detailed way, you can do this:
Distance from A to B to A again = 16m
Distance from A to B = 8m
Period (A to B to A again) = 24 seconds
Time (t) from A to B =???
O to B is quarter of the period so the answer would be = 6 sec
Or you can follow the above pattern:
Distance from A to B to A again = 16m
Distance from O to B = 4m
Period (A to B to A again) = 24 seconds
Time (t) from O to B =???
c) O to C
This is one eight of the period which would be = 3 seconds
Or by detailed calculation:
Distance from A to B to A again = 16m
Distance from O to C = 2m
Period (A to B to A again) = 24 seconds
Time (t) from O to C =???
d) D to E
Note with this question, if you observe the diagram carefully you will see that you weren’t given the distance between D to E directly. However this can easily be found by subtracting the distance O to D from the distance O to E and this would give you the distance from D to E.
Distance from A to B to A again = 16m
Distance from D to E = 3.5 – 3 = 0.5m
Period (A to B to A again) = 24 seconds
Time (t) from D to E =???
1 Response to Calculating Simple Harmonic Motion Questions
Absolutely interesting post.
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